Solve sin2alpha/cos3alpha= | Microsoft Math Solver

獲取有關算術，代數，圖形計算器，三角學，微積分等的幫助。

... .org/questions/if-kappa-cos-2pi-9-i-sin-2pi-9-i-e-the-primitive-complex-9-th-root-of-1-then-how. SolvePractice主題代數前意味著模式最大的共同因素最小公共倍數動作順序分數混合分數優質保理指數基代數組合類似條款變數的求解因素擴大評估分數線性方程二次方程不等式方程式系統矩陣三角簡化評價圖求解方程微積分衍生物積分限制代數計算機三角計算機微積分計算機矩陣計算機下載主題代數前意味著模式最大的共同因素最小公共倍數動作順序分數混合分數優質保理指數基代數組合類似條款變數的求解因素擴大評估分數線性方程二次方程不等式方程式系統矩陣三角簡化評價圖求解方程微積分衍生物積分限制代數計算機三角計算機微積分計算機矩陣計算機解決代數三角統計微積分矩陣變數清單\frac{\sin2\alpha}{\cos3\alpha}=評估\frac{2\sin(\alpha)}{-4\left(\sin(\alpha)\right)^{2}+1}對α微分\frac{2\cos(\alpha)\left(5\left(\sin(\alpha)\right)^{2}+\left(\cos(\alpha)\right)^{2}\right)}{\left(\left(\cos(\alpha)\right)^{2}-3\left(\sin(\alpha)\right)^{2}\right)^{2}}測驗Trigonometry5類似於:\frac{\sin2\alpha}{\cos3\alpha}=來自Web搜索的類似問題If\displaystyle\kappa={\cos{{\left(\frac{{{2}\pi}}{{9}}\right)}}}+{i}{\sin{{\left(\frac{{{2}\pi}}{{9}}\right)}}}(i.e.theprimitiveComplex\displaystyle{9}throotof\displaystyle{1})...https://socratic.org/questions/if-kappa-cos-2pi-9-i-sin-2pi-9-i-e-the-primitive-complex-9-th-root-of-1-then-how\displaystyle\kappa^{{8}}=-\kappa^{{5}}-\kappa^{{2}} Explanation: Consider: \displaystyle\kappa={\cos{{\left(\frac{{{2}\pi}}{{9}}\right)}}}+{i}{\sin{{\left(\frac{{{2}\pi}}{{9}}\right)}}}...Whysquaringthetrigonometricequationchangesthesolution?https://math.stackexchange.com/questions/2024367/why-squaring-the-trigonometric-equation-changes-the-solutionIfyousquare,youalsogetthesolutionsof\sin\alpha-\cos\alpha=-\frac{1}{2}Ingeneral,ifyouhaveanequationoftheformf(x)=g(x)andsquarebothsides,youget,afterrearranging,f(x)^2-g(x)^2=0\tag{*}...Exactvalueof\tan^2\alpha-\cot^2\alpha?https://math.stackexchange.com/q/2643154Squaring\sin\alpha-\cos\alpha=\frac13,weget\sin^2\alpha-2\sin\alpha\cos\alpha+\cos^2\alpha=\frac19\\\sin\alpha\cos\alpha=\frac{4}{9}whichhelpsyouwiththedenominatorofyour...Proofofsumofsinustermswithmathematicalinduction.https://math.stackexchange.com/questions/461247/proof-of-sum-of-sinus-terms-with-mathematical-inductionHINT(forP(1))\cos2x=\cos^2x-\sin^2xTrajectoryofprojectilethrowndownhillhttps://physics.stackexchange.com/q/24235AsfarasIsee,a_y=-k\cos(\varphi)<0,buta_x=k\sin(\varphi)>0!Atleastifyouarethrowingtheprojectileinthedownwarddirection...Findtheimaginarypartofthissumhttps://math.stackexchange.com/questions/158069/find-the-imaginary-part-of-this-sum\begin{align}S&=e^{ia}\sum_{k=0}^\infty\left(\frac{e^{i2\alpha}}{3}\right)^k\\&=\frac{3e^{i\alpha}}{3-e^{i2\alpha}}\cdot\frac{3-e^{-i2\alpha}}{3-e^{-i2\alpha}}\\&=\frac{9e^{i\alpha}-3e^{-i\alpha}}{10-6\cos(2\alpha)}\\&=\frac{6\cos(\alpha)+12i\sin(\alpha)}{10-6\cos(2\alpha)}\\&=\color{red}{\frac{3\cos(\alpha)}{5-3\cos(2\alpha)}}+i\color{green}{\frac{6\sin(\alpha)}{5-3\cos(2\alpha)}}\end{align}...更多結果共享復制已復制到剪貼板示例二次方程式{x}^{2}-4x-5=0三角學4\sin\theta\cos\theta=2\sin\theta線性方程y=3x+4算術699*533矩陣\left[\begin{array}{ll}{2}&{3}\\{5}&{4}\end{array}\right]\left[\begin{array}{lll}{2}&{0}&{3}\\{-1}&{1}&{5}\end{array}\right]聯立方程\left.\begin{cases}{8x+2y=46}\\{7x+3y=47}\end{cases}\right.微分\frac{d}{dx}\frac{(3x^{2}-2)}{(x-5)}積分\int_{0}^{1}xe^{-x^{2}}dx限制\lim_{x\rightarrow-3}\frac{x^{2}-9}{x^{2}+2x-3}返回頂部